Question 35551
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{ 9x^2-270=0 }}}
a = 9
b = 0
c = -270
{{{x = (-0 +- sqrt( 0^2-4*9*(-270) ))/(2*9) }}}
Working left to right inside the root
{{{x = ( 0 +- sqrt( -4*9*(-270) ))/(2*9) }}}
{{{x = ( 0 +- sqrt( -36*(-270) ))/(2*9) }}}
{{{x = ( 0 +- sqrt( -36*(-270) ))/(2*9) }}}
{{{x = ( 0 +- sqrt( 9720) )/(2*9) }}}
and the denominator
{{{x = ( 0 +- sqrt( 9720) )/(18) }}}
Now the root itself
{{{x = ( 0 +- 18 (sqrt(30)) )/(18) }}}
Reduce the fraction
{{{ x = (sqrt(30)) }}} and {{{ x = - (sqrt (30)) }}}