Question 302401
Factorise: (y^2 + 4y - 5) = (y + 5)(y - 1)
Factorise: (y^2 - 25) = (y+5)(y-5) 

Therefore, 

{{{(y + 5)(y - 1)}}}÷{{{((y+5)(y-5)/(y+7))}}}


{{{(y + 5)(y - 1)}}}*{{{((y+7)/(y+5)(y-5))}}}

cancel out (y+5) 


{{{((y - 1)(y+7))/(y-5))}}}