Question 302294
Find the vertex of the parabola.
y = -4x^2 - 16x - 11
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Vertex occurs at x = -b/2a = 16/(-8) = -2
f(-2)= -4(-2)^2 - 16(-2) - 11
f(-2) = -16 + 32 - 11
f(-2) = 5
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Vertex:: (-2,5)
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Cheers,
Stan H.