Question 302244
{{{3n^2 + n + 3}}}

{{{n = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
where a = 3, b = 1 and c = 3

{{{n = (-1 +- sqrt( 1^2-4*3*3 ))/(2*3) }}} 


{{{n = (-1 +- sqrt(-35))/(6) }}} 


{{{n = (-1 +- (35i))/(6) )}}}