Question 302227
((4x^2-9)/(-4x-6))/((6x-9)/(4x+4))

factorise: 4x^2-9 = (2x-3)(2x+3)
factorise: -4x-6  = -2(2x+3)
factorise: 6x-9 = 3(2x-3)
factorise: 4x+4 = 4(x+1)

((2x-3)(2x+3)/(-2(2x+3)))*((4(x+1)/3(2x-3))

cancel out "2x-3" and "2"

= {{{(-2*(2x+3)(x+1))/(3*(2x-3))}}}