Question 302203
2x^2-7x-1=0 

Using quadratic formulas: {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}

where a = 2, b = -7 and c = -1 

{{{x = (-(-7) +- sqrt( (-7)^2-4*2*(-1) ))/(2*(2)) }}}
{{{x = (7) +- sqrt( (49-(-8) )/4) }}}
{{{x = (7) +- sqrt( (49+8) )/4) }}}
{{{x = (7) +- sqrt( (57) )/4) }}}

x = 5.11 or x = 8.89