Question 4660
Let's take the first given ordered pair, (-2, ?) which you could write in more familiar terms (x, y) or (-2, y) and rewrite the equation in more familiar notation:
 y = x^2 + 4x + 5  Substitute x = -2 and solve for y:

y = (-2)^2 + 4(-2) + 5
y = 4 - 8 + 5
y = 1 

The first ordered pair is (-2, 1)

Now the second given ordered pair, (x, 2):

y = x^2 + 4x + 5  Substitute y = 2 and solve for x.
2 = x^2 + 4x + 5  Subtract 2 from both sides.
x^2 + 4x + 3 = 0  Factor.
(x + 1)(x + 3) = 0  Apply the zero products principle.

x + 1 = 0; x = -1  or x + 3 = 0;  x = -3

The second ordered pair is: (-1, 2) or (-3, 2)