Question 301937
If it's 2 points at random, it's not possible.  3 non-colinear points are necessary.
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If the 2 points are the intersections with the same axis, eg:
(3,0) and (5,0) then
(x-3)*(x-5) = 0
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(a,0) and (b,0) --> (x-a)*(x-b) = 0