Question 301799
Dimensions of a triangle. 
A triangle is 10 cm wider than it is tall. 
The area 48 cm^2 is Find the height and the base
:
Let x = the height
then
(x+10) = the base
:
Area of a triangle
{{{1/2}}}*b*h = A
in this problem
{{{1/2}}}*(x+10)*x = 48
{{{1/2}}}*(x^2 +10x) = 48
multiply both sides by 2, to get rid of the fraction, results
x^2 + 10x = 96
A quadratic equation
x^2 + 10x - 96 = 0
Factors to
(x+16)(x-6) = 0
positive solution 
x = 6 is the height
and obviously, 16 = the base
:
Check your solution in the Area of a triangle equation