Question 301927
(x^2-5x+4)/(x^2-9x+8)÷(x^2-12x+32)

x^2-4x-x+4 / (x^2-8x-x+8) divided by (x^2-8x-4x+32)

x(x-4)-1(x-4)/x(x-8)-1(x-8) / {x(x-8)-4(x-8)}

(x-1)(x-4)/(x-1)(x-8)  / (x-8)(x-4)

(x-4)/(x-8) * 1/(x-8)(x-4)

1/ (x-8)^2