Question 301827
A 60% acid solution is to be mixed with a 80% acid solution to produce 20 liters of a 65% acid solution.  How many liters of each solution is needed?  I tried setting up a table but that didn't work.  Can you please explain how you derive at your answer.  Thanks and have a wonderful weekend.

60% acid required be x 
80% acid required will be 20-x

Total 20 liters 65%

0.6x +0.8(20-x)=20*0.65

0.6x+16-0.8x=13.00

-0.2x= -16+13
-0.2x=-3
x= -3/-0.2

x=15  liters 60% acid required

balance 5 liters will be 80% acid

Ananth