Question 301768
this is what you say the problem is as u have written it
{{{(((a/(a+x))/((a+x)/b))(a+x))/2ab)}}} 
first when u have a fraction over a fraction its a lot easier to calculate if u multiply the top fraction by the reciprical of the bottom fraction.
{{{((a/(a+x))(b/(a+x))(a+x))/2ab)}}} 
since a+x is in numerator and there is one a+x in denomerator and they are being multiplied they can be cross cancelled out
{{{((a/(a+x))(b/cross(a+x))cross(a+x))/2ab)}}} 
{{{((a/(a+x))(b/1)/2ab)}}}
multiply the numerators
{{{((ab/(a+x))/2ab)}}}
same thing as befor, when u have a fraction over a fraction its a lot easier to calculate if u multiply the top fraction by the reciprical of the bottom fraction.
{{{((ab/(a+x))/(2ab/1))}}}
{{{(ab/(a+x))(1/2ab))}}}
cross cancell the ab
{{{(cross(ab)/(a+x))(1/2cross(ab)))}}}
{{{(1/(a+x))(1/2)))}}} 
multiply across
{{{1/2(a+x)}}}