Question 301632
Let N and N+2 be your odd integers.
{{{N(N+2)=2(N+N+2)-1}}}
{{{N^2+2N=2(2N+2)-1}}}
{{{N^2+2N=4N+3}}}
{{{N^2-2N-3=0}}}
{{{(N-3)(N+1)=0}}}
Since we're only looking for the positive answer, we won't solve the negative solution.
{{{N-3=0}}}
{{{N=3}}}
The two integers are then 3 and 5.
Verify the solution by using the original equation.