Question 301424
{{{7(x-2)(x+5)}}} and {{{2(x+5)^2}}}
{{{7(x-2)(x+5)}}} and {{{2(x+5)(x+5)}}}
the only things that are in common is that they both have {{{(x+5)}}}
so if we take away 1 (x+5) from both numbers i.e. {{{7(x-2)cross(x+5)}}} and {{{2(x+5)cross(x+5)}}}
and then just multiply what is left to find the least common multiple
{{{7(x-2)}}} and {{{2(x+5)}}}
{{{14(x-2)(x+5)}}} or {{{14(x^2+3x-10)}}} or {{{14x^2+42x-140)}}}