Question 301368
{{{f(x)}}} can take on values of {{{x}}} when {{{x>0}}} and and {{{-x}}} when {{{x<0}}}.
{{{f(x)=g(x)}}}
Create a new function and find out when it equals zero.
{{{h(x)=f(x)-g(x)=0}}}
When {{{x>=0}}}
{{{h(x)=x-(x-1)}}}
{{{h(x)=1}}}
When {{{x<0}}}
{{{h(x)=-x-(x-1)=-2x+1}}}
.
.
.
In both cases, {{{h(x)}}} will never equal zero.
No solutions where f(x)=g(x).