Question 301224
The height of a ball is modeled by the equation y=-1/70 x^2+2x+2 where x is the horizontal feet and y the vertical feet. 
A) How high is the ball when you hit it?
Assuming x is the distance from where it's hit:
x = 0 --> y = 2
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B) What is the ball's maximum heigh?
It's a parabola, find the vertex:
@ x = -b/2a = -2/(-1/35) = 70
y = -(1/70)*70^2 + 140 + 2
y = 72
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C) How far from where you hit the ball does it strike the ground? 
At y = 0
-x^2/70 + 2x + 2 = 0
*[invoke solve_quadratic_equation -1/70,2,2]

=~ 140.993 feet