Question 301307
Solve for x:
{{{20x^2-82x+80 = 0}}} First factor 2.
{{{2(10x^2-42x+40) = 0}}} so that...
{{{10x^2-41x+40 = 0}}} Factor the trinomial.
{{{(2x-5)(5x-8) = 0}}} Apply the zero product rule.
{{{2x-5 = 0}}} or {{{5x-8 = 0}}}
{{{2x = 5}}} or {{{5x = 8}}}
{{{highlight(x = 5/2)}}} or {{{highlight(x = 8/5)}}}