Question 301264
2log(x^2+4x)=1 
log(x^2+4x)^2=1 
(x^2+4x)^2=10^1
(x^2+4x)^2=10
x^2+4x=sqrt(10)
x^2+4x-sqrt(10) = 0
x^2+4x-3.162 = 0
Using the quadratic formula we get:
x={0.676, -4.676}
.
Details of quadratic:
*[invoke quadratic "x", 1, 4, -3.1622776601683793319988935444327 ]