Question 301067
Find the area of a regular hexagon which has a perimeter of 36 meters
Each side is 6 meters (36/6)
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The area of any regular polygon with n sides of length s is:
{{{Area = ns^2*cot(180/n)/4}}}
{{{Area = 6*36*cot(30)/4}}}
= {{{54*cot(30)}}}
= {{{54sqrt(3)}}} sq meters