Question 300887
{{{(x^2+3x)/(x^2-4)-(6x+10)/(x^2-4)=(x^2+3x-6x-10)/(x^2-4)}}}
{{{(x^2+3x)/(x^2-4)-(6x+10)/(x^2-4)=(x^2-3x-10)/(x^2-4)}}}
{{{(x^2+3x)/(x^2-4)-(6x+10)/(x^2-4)=((x-5)(x+2))/((x-2)(x+2))}}}
{{{(x^2+3x)/(x^2-4)-(6x+10)/(x^2-4)=((x-5)cross((x+2)))/((x-2)cross((x+2)))}}}
{{{(x^2+3x)/(x^2-4)-(6x+10)/(x^2-4)=(x-5)/(x-2))}}}