Question 300841
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The perimeter of any figure is just the sum of the measures of the sides, hence the perimeter of a square is simply four times the measure of one of the sides.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P_o\ =\ 4s]


but if you increase the measure of the sides by a factor of four, then each side  now measures *[tex \LARGE 4s], and the perimeter becomes:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P_n\ =\ 4(4s)]


Hence the new perimeter is 4 times larger than the original perimeter:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P_n\ =\ 4P_o]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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