Question 300818
I'm at a loss here.  I've derived an answer but I'm lost as to whether it is correct.

Find the LCD for the given rational expressions, and convert each rational expression into an equivalent rational expression with the LCD as the denominator.
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{{{(-3)/(2p^2+7p-15)}}},{{{p/(2p^2-11p+12)}}},{{{2/(p^2+p-20)}}}

{{{(-3)/((2p-3)(p+5))}}},{{{p/((p-4)(2p-3))}}},{{{2/((p-4)(p+5))}}},{{{LCD=(2p-3)(p+5)(p-4)}}}

The first denominator lacks the factor {{{(p-4)}}} so multiply both its
numerator and denominator by that factor:

{{{(-3(p-4))/((2p-3)(p+5)(p-4))}}},{{{p/((p-4)(2p-3))}}},{{{2/((p-4)(p+5))}}},{{{LCD=(2p-3)(p+5)(p-4)}}}

The second denominator lacks the factor {{{(p+5)}}} so multiply both its
numerator and denominator by that factor:

{{{(-3(p-4))/((2p-3)(p+5)(p-4))}}},{{{(p(p+5))/((p-4)(2p-3)(p+5))}}},{{{2/((p-4)(p+5))}}},{{{LCD=(2p-3)(p+5)(p-4)}}}

The third denominator lacks the factor {{{(2p-3)}}} so multiply both its
numerator and denominator by that factor:

{{{(-3(p-4))/((2p-3)(p+5)(p-4))}}},{{{(p(p+5))/((p-4)(2p-3)(p+5))}}},{{{(2(2p-3))/((p-4)(p+5)(2p-3))}}},{{{LCD=(2p-3)(p+5)(p-4)}}}

If you multiply the tops out and rearrange the factors on the
bottoms, you DO get #5.

Edwin</pre>