Question 35472
(x+5)^2 + 4(y-4)^2 = 16 original
((x+5)^2)/16 + ((y-4)^2)/4 = 1 divide by 16 to get the side to equal 1
the major axis is the highest value (16)^(1/2)
the major axis is 4 units long, and the major axis is horizontal
the minor axis, on the other hand, is the lower value (4)^(1/2)
the minor axis is 2 units long
the center is found by: ((x-h)^2)/a^2 + ((y-k)^2)/b^2 = 1
where a is the length of the minor axis and b is the length of the minor axis and (h,k) is the center
the center is (-5,4)
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To Graph: go to the point (-5,4) and make points 4 units left and right of that point....also, go 2 units up and down from the center....connect the dots (excluding the center) to make an ellipse