Question 300757
 2. Assume the body temperatures of healthy adults are normally distributed with a mean of 98.20 °F and a standard deviation of 0.62 °F (based on data from the University of Maryland researchers).
a. If you have a body temperature of 99.00 °F, what is your percentile score?
Find the z-score for 99.
Find the percent of population with a z-score that is less than
the z-score for 99. 
The is the percentile score of 99
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b. Convert 99.00 °F to a standard score (or a z-score).
You've had to do that in the "a" problem.
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c. Is a body temperature of 99.00 °F unusual? Why or why not?
If its z-score is less than -2 or more than +2 it is considered
to be "unusual".
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d. Fifty adults are randomly selected. What is the likelihood that the mean of their body temperatures is 97.98 °F or lower?
Find the z-score of 97.98 using mean = 98.2 and std = 0.62/sqrt(50)
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e. A person’s body temperature is found to be 101.00 °F. Is the result unusual? Why or why not? What should you conclude?
Find the z-score of 101 and make your conclusion.
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f. What body temperature is the 95th percentile?
Find the z-score with a left tail of 0.95.
Convert to a temperature score using temp = z*s+u
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g. What body temperature is the 5th percentile?
Findt the z-score with a left tail of 5%.
Convert to a temperature score using temp = z*s+u
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h. Bellevue Hospital in New York City uses 100.6 °F as the lowest temperature considered to indicate a fever. What percentage of normal and healthy adults would be considered to have a fever?
Find the z-score of 100.6.
Find the percent population above that z-score.

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Does this percentage suggest that a cutoff of 100.6 °F is appropriate? 
Make your judgement.
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Cheers,
Stan H.