Question 300750
ten years ago a man was as old as his wife is now. The man is now twice as old as his wife was then. How old are they both now?

let the wife's age be x now

Let the husband's age be y now

y-10 =x

y=2(x-10)

y-x=10

y-2x=-20

y-x -y+2x=-20-10

-x=-30

x= 30 wife's age now

y-10=x
y-10=30

y=40 the husband's age now