<PRE><B>Question 35464</B>
The equation of a circle with radius r and center at (h, k) is 
{{{(x-h)^2 + (y-k)^2= r^2}}}


Therefore the equation is 
{{{(x-4)^2 + (y+3)^2= 25}}}


Expanding:
{{{x^2 -8x + 16 + y^2 + 6y + 9 = 25}}}


Write it in standard form:
{{{x^2 + y^2 - 8x + 6y = 0}}}, which incidentally, passes through the origin.


R^2 at SCC</PRE>