Question 300391
Use the distance formula,
{{{D^2=(x2-x1)^2+(y2-y1)^2}}}

{{{D^2=(12-0)^2+(3-5)^2}}}
{{{D^2=(12)^2+(-2)^2}}}
{{{D^2=144+4}}}
{{{D=sqrt(148)}}}
I leave it to you to get the decimal approximation you need.