Question 300399
original number: (ab)=10a+b
new number: (ba)=10b+a
a+b=11
(ba)=9+10a+b

hmm this is harder to explain then i thought.
[for example take number 45=(10(4)+5) if reversed its 54=(10(5)+4). 4+5=9 sum of digits of original number 45, (10(4)+5)+9=54 added 9 to the original 45 to get the new number 54.]
same type of thing for this problem
a and be have to be single whole numbers that add to get 11
{{{(ba)=(ba)}}} {{{b=11-a}}}
{{{(9+10a+b)=(10b+a)}}}
{{{9=9b-9a}}}
{{{9=9(11-a)-9a}}}
{{{9=(99-9a)-9a}}}
{{{9=99-18a}}}
{{{-90=-18a}}}
{{{5=a}}}
________
{{{a+b=11}}}
{{{5+b=11}}}
{{{b=6}}}
________
check
(ab)=10a+b
(ab)=10(5)+(6)
(ab)=(56)
__
(ba)=10b+a
(ba)=10(6)+(5)
(ba)=(65)
__
(ba)=9+(ab)
(65)=9+(56)
(65)=(65)
CORRECT