Question 300127
{{{((9-6i))/((7+8i))}}}
:
Multiply by the conjugate of the denominator over itself (same as mult by 1)
{{{((9-6i))/((7+8i))}}} * {{{((7-8i))/((7-8i))}}} = {{{(63 - 72i - 42i + 48i^2)/(49 - 56i + 56i - 64i^2)}}} = {{{(63 -114i + 48(-1))/(49 - 64(-1))}}} = {{{(63 - 114i - 48)/(49 + 64)}}} = {{{(15 - 114i)/113}}}