<PRE><B>Question 300181</B>
A student ran out of time on a multiple choice exam and guessed the answers for two problems. 
Each problem had 4 answer choices - a,b,c,d- and only one correct answer. 
What is the probability that he answered both of the problems correctly? 
Write your answer as a fraction in lowest terms.
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P(1st correct) = 1/4
P(2nd correct) = 1/4
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P(both correct) = (1/4)^2 = 1/16
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Cheers,
Stan H.
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