Question 299975
Three times the greater of two consecutive odd integers is five less than four times the smaller. Find the two numbers. 
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1st odd integer: 2x-1
Next odd integer: 2x+1
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Equations:
3(2x+1) = 4(2x-1)-5
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6x+3 = 8x-4-5
6x+3 = 8x-9
2x = 12
x = 6
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1st odd: 2(6)-1 = 11
2nd odd: 2(6)+1 = 13
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Cheers,
Stan H.
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