Question 299748
Let {{{a}}} = the smaller number
Let {{{b}}} = the larger number
given:
{{{b = 2a}}}
{{{3a = b + 20}}}
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By substitution,
{{{3a = 2a + 20}}}
subtract {{{2a}}} from both sides
{{{a = 20}}}
and, since
{{{b = 2a}}}
{{{b = 2*20}}}
{{{b = 40}}}
The numbers are 20 and 40
check:
{{{3a = b + 20}}}
{{{3*20 = 40 + 20}}}
{{{60 = 60}}}
OK