Question 299584
Find the perimeter and area of a right triangle if the shortest side is 12 in. and the longest side is 37 in. Include correct units with each part of your solution.


Let x be the third side. Then by the Pythagorean Theorem we have:

x^2 + 12^2 = 37^2
x^2 + 144 = 1369
x^2 = 1369-144
x^2 = 1225
x = 35

The perimeter Of the triangle is 12+35+37 = 84 

The area, using the formula Area = (base*height)/2, is:

(35*12)/2 = 210