Question 299536
what is the answer to, log(x+4)+log5=log10x

By a law of logs we have log(x+4) + log(5) = log((x+4)*5) so we have:

log((x+4)*5) = log(10x) so

(x+4)*5 = 10x
5x + 20 = 10x
5x = 20
x = 4