Question 299542
Can someone solve this, 3logx=1/2log256-log2
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I suppose you want to solve for x?
{{{(1/2)log(256) = log(sqrt(256)) = log(16)}}}
{{{3log(x) = log(x^3)}}}
--> {{{log(x^3) = log(16) - log(2) = log(8)}}}
{{{x^3 = 8}}}
x = 2 (principal value)