Question 299593
A baseball is thrown straight upwards with an initial velocity of 224 ft/s.
At what time(s) does the ball reach 832 feet?
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h(t) = -16t^2 + 224t gives the height in feet as a function of t in seconds.
832 = -16t^2 + 224t
-t^2 + 14t - 52 = 0
*[invoke solve_quadratic_equation -1,14,-52]
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Looks like it's on May 32nd.
It doesn't go that high, it's max height is 784 feet at 7 seconds.