Question 299456
In the triangle ABC, side a=7, b=6, and c=8. Find angle B to the nearest degree?


{{{Cos(B)=(a^2+c^2-b^2)/(2ac)}}}

{{{Cos(B)=(a^2+c^2-b^2)/(2*a*c)}}}

{{{Cos(B)=(7^2+8^2-6^2)/(2*7*8)}}}

{{{Cos(B)=(49+64-36)/112}}}

{{{Cos(B)=77/112}}}

{{{Cos(B)=11/16}}}

{{{Cos(B)=0.6875}}}

{{{B="46.56746344°"}}}

To the nearest degree:

{{{B="47°"}}}

Edwin</pre>