Question 299365
First, get both equations into slope-intercept form.

EQ1) 
3y+2x=4
3y = -2x + 4
y = -(2/3)x + 4/3
y-intercept is where x=0:  (0,4/3)
x-intercept is where y=0:  (2,0)
With two points you can plot the line.

EQ2) 
2y-6x=-12
y-3x = -6
y = 3x-6
y-intercept:  (0,-6)
x-intercept:  (2,0)
You can plot this line too.  But you see it is the intersection.

{{{graph(500,500,-10,10,-10,10,-2/3*x+4/3,3*x-6)}}}