Question 299158
Solve by the LCM method:

{{{6/(y+3)+ 2/y =(5y-3)/(y^2-9)}}}


{{{6(y)(y - 3) + 2(y^2 - 9) = y(5y - 3)}}}-------- Multiply by LCD, {{{y*(y - 3)(y + 3))}}}


{{{6(y^2 - 3y) + 2y^2 - 18 = 5y^2 - 3y}}}


{{{6y^2 - 18y + 2y^2 - 18 = 5y^2 - 3y}}}


{{{6y^2 + 2y^2 - 5y^2 - 18y + 3y - 18 = 0}}}


{{{3y^2 - 15y - 18 = 0}}}


{{{3(y^2 - 5y - 6) = 3(0)}}}


{{{y^2 - 5y - 6 = 0}}}


(y - 6)(y + 1) = 0


{{{highlight_green(y = 6)}}} or {{{highlight_green(y = - 1)}}}