Question 299158
{{{6/(y+3)+ 2/y =(5y-3)/(y^2-9)}}}

6 / y+3 -5y-3 / y^2-9= 2/y

6(y-3) - (5y-3) / y^2-9  = 2/y

6y-18 -5y+15 = 2(y^2-9) /y

y-3= 2(y^2-9) /y

y(y-3)= 2 (y^2-9)

y= 2(y+3)(y-3) / (y-3)

y=2(y+3)

y=2y+6

y=-6

Ananth