Question 298995
There is an equilaterial triangle and it cuts it down the middle to form to right triangles.
 The whole base of the triangle is 24 however, if you cut it in half the base of the 2 right triangles equal 12.
 The bottom angle on the triangle across from the right angle equals 65 degrees.
 Using cosine, sin, or tangent find the values of x and y. X is the hypotenuse
 on both right triangles and y is the leg that cuts the triangle in half. 
:
You can find x using the cosine of 65,
where
x = hypotenuse
12 = side adjacent
cos(65) = {{{12/x}}}
.4226x = 12
x = {{{12/.4226}}}
x = 28.39 ~ 28
and
find y using the tan of 65
where
side opposite = y
side adjacent = 12
tan(65) = {{{y/12}}}
y = 2.445*12
y = 25.73 ~ 26
:
:
check solution by finding the sine of a, it should equal 65
sin(a) = 25.73/28.39
sin(a) = .9064
a = 65.0