Question 298952
simplify
{{{(x^2+7x)/(3x)}}}
------------
{{{(49-x^2)/(3x-21)}}}
:
Invert the dividing fraction and multiply:
{{{(x^2+7x)/(3x)}}} * {{{(3x-21)/(49-x^2)}}}
:
factor and cancel x, (x+7), (x-7) and 3. just leaving us with one
{{{(x(x+7))/(3x)}}} * {{{(3(x-7))/(7-x)(7+x))}}} = 1