Question 298644
{{{ 2^n=(3^(n-2))^(1/2) }}}
{{{2^2n = 3^(n-2)}}}
2n*log(2) = (n-2)*log(3)
2n*log(2) = n*log(3) - 2log(3)
2nlog(2) - nlog(3) = -log(9)
n*(log(3) - log(4)) = log(9)
n = log(9)/(log(3) - log(4))
n =~ -7.63768