Question 298476
I'm having trouble with writing the inverse of a the function f(x)=e^(x-2). I've plugged in given plotting points of x= -6, -4, -2, 0, 2, 4, and 6. For the inverse, do I write x=lne^(y-2) and bring my exponent to the front of ln? Thank you in advance for your help.
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Note: The asymptote for y = e^(x-2) is a horizontal axis; it is
y = 0. The (x-2) moves the graph 2 to the right but does not change
the horizontal asymptotel
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To find the inverse proceed as follows: 
f(x)=e^(x-2)
Interchange x and y to get:
x = e^(y-2)
Now solve for "y":
ln(x) = y-2
y = ln(x)+2 is the inverse
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Part 2: is my vertical asymptote 2 for the inverse?
The asymptote is now a vertical asymptote.  The 2 raises
the curve but that has no effect on a vertical asymptote.
Just as the horizontal asymptote on the function was y = 0,
the inverse has a vertical asymptote and it is x = 0
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Cheers,
Stan H.
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