Question 298332
I got 10 as my answer which you have to admit is a nice small even number.

I would not do it left to right.
Follow pemdas rules of order of operations
I would also hold off on making numbers bigger. There is often a way to cancel things if you leave them in factored form
Actually let's do the right hand side
5(2/(2-7))(5)
2-7=-5
-5*2/-5*5
=10
(4-2(3-1))
3-1=2
4-2*2=0
I was right to hold off on multiplying
anything times 0 =0 so we are left with ten

so how you changed 4-2*2 in4-2+2
(4-2+2) = 2 so instead of zero you got 2