Question 35349
factor completely
{{{x^3+3x^2-4x-12}}}

okay you have to divide this problem

{{{x^3+3x^2}}}  and -4x-12


First in {{{x^3+3x^2}}} you can factor out the common item x^2.... so it will be

x^2(x+3)

Now the common here -4

-4(x+3)

see how the x+3 repeat twice.... so make it one and put the x^2 and the -4 together. In other words

(x^2-4)*(x+3)