Question 298112
A lady is three times as old as her daughter. 
8 years ago the product of their ages was 112. 
find their present ages.
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Equations:
L = 3D
(L-8)(D-8) = 112
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Substitute for "L" and solve for "D":
(3D-8)(D-8) = 112
3D^2 -32D + 64 = 112
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Rearrange:
3D^2 -32D - 48 = 0
Factor:
(3D+4)(D-12) = 0
D = 12 (daughter's age)
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Since L = 3D, L = 36 (the lady's age)
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Cheers,
Stan H.
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