Question 298100
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If *[tex \Large f(0)\ =\ 2], then the point *[tex \Large \left(0,2\right)] is on the graph of the function.  Likewise if *[tex \Large f(9)\ =\ 5], then the point *[tex \Large \left(9,5\right)] is on the graph of the function.


Now that you have two points, use the two-point form of the equation of a line to write your equation.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ \left(\frac{y_1\ -\ y_2}{x_1\ -\ x_2}\right)(x\ -\ x_1) ]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ 2\ =\ \left(\frac{2\ -\ 5}{0\ -\ 9}\right)(x\ -\ 9) ]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(x)\ =\ y\ =\ \frac{1}{3}x\ -\ 1]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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