Question 297967
sq rt x-3 + sq rt 2x=3

the first thing that needs to be done is getting rid of the radical and to do so you need to square both sides of the equation.

(sq rt x-3 + sq rt 2x)^2 = 3^2

then you have

x-3+2x=9

then you add together like terms

3x-3=9

then subtract 3 from both sides of the equation

3x=12

then to solve for x you need to devide both sides of the equation by three and the final answer is

x=4