Question 4624
you would add them as you would any fractions...look for the lowest common multiple etc.


So, {{{4/x^3y + 7/xy^2}}} will need {{{x^3y^2}}} as the denominator. If this is so, then the first term will have to be multiplied by y/y (ie 1) and the second term will have to be multiplied by {{{x^2/x^2}}}, as:


{{{(4/x^3y)(y/y) + (7/xy^2)(x^2/x^2)}}}


{{{(4y/x^3y^2) + (7x^2/x^3y^2)}}}


giving your answer --> {{{((4y+7x^2)/x^3y^2)}}}


jon